Parse URL Params

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题目

You're required to implement a type-level parser to parse URL params string into an Union.

ParseUrlParams<":id">; // id
ParseUrlParams<"posts/:id">; // id
ParseUrlParams<"posts/:id/:user">; // id | user

解答

type ParseUrlParams<T extends string> = T extends `${string}:${infer R}`
  ? R extends `${infer F}/${infer L}`
    ? F | ParseUrlParams<L>
    : R
  : never;